Board 14 North Deals | | ♠ | 9 | | ♥ | A J 10 3 | | ♦ | Q 10 6 4 | | ♣ | A J 7 2 | |
| ♠ | J 3 2 | | ♥ | 7 2 | | ♦ | J 3 | | ♣ | K Q 10 9 6 4 | | | | | | | ♠ | K 8 7 6 5 | | ♥ | 9 8 5 4 | | ♦ | 9 8 2 | | ♣ | 3 | |
|
| | ♠ | A Q 10 4 | | ♥ | K Q 6 | | ♦ | A K 7 5 | | ♣ | 8 5 | |
| West | North | East | South |
| | 1 ♦ | Pass | 2 ♠ |
| Pass | 3 ♣ | Pass | 3 ♦ |
| Pass | 3 NT | Pass | 4 NT |
| Pass | 6 ♦ | All pass | |
Here 3 ♣ shows a second suit and 3 ♦ is normally minimum but could be a slam try. The 3 ♦ rebid denies a singleton heart at least. Showing a singleton club is difficult. Without a singleton or void responder's only ways to show extra values are 4 ♦ or possibly 3 NT but we have not settled on an appropriate range for 3 NT. Responder's next bid of 4 NT reveals the slam try.
Opener has shown around 12-14. The 1=4=4=4 shape is bad - no trump length. And there are only 12 hcp. However two aces and the ♦ Q are all working and we know there are not two quick losers in spades. Perhaps the jump to 6 ♦ is optimistic but the contract can make seven with just one finesse.
An artificial system option to be able to show the club singleton is to swap opener's 3 ♣ and 3 ♦ rebids. With 3 ♣ showing diamonds and 3 ♦ showing clubs but with extra values. Over 3 ♣, showing diamonds, this allows responder to bid 3 ♦ with a club singleton and three of the other major to show a singleton there.
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